Essay Question Osmosis

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Table 1.1-Presence of Glucose in Water through a Dialysis Bag Group 2, 4, 6 and 8 do not have any data for distilled water, 0.2M Sucrose, and 0.4M Sucrose and group 1, 3, 4 and 7 do not have any data for 0.6M Sucrose, 0.8M Sucrose and 1.0M Sucrose because of the lack of time.

So, group 1 and 2 were paired up, 3 and 4, 5 and 6, and 7 and 8 to exchange data.

Four cores were then put into each beaker of sucrose solution.

Plastic wrap was then given to cover the beakers, preventing evaporation when left to stand overnight.

Table 1.4: Individual Data of Change in Mass of Potato Cores in Six Different Sucrose Solution Group 2, 4, 6 and 8 do not have any data for distilled water, 0.2M Sucrose, and 0.4M Sucrose and group 1, 3, 4 and 7 do not have any data for 0.6M Sucrose, 0.8M Sucrose and 1.0M Sucrose because of the lack of time.

From table 1.1 in this part of the lab, it is seen that IKI is flowing into the bag and glucose is flowing out of the bag. Knowing of this process is due to the color transformation of the bag, therefore showing that IKI has penetrated the bag.By testing the beaker for the existence of glucose, it was found that the glucose permeated through the dialysis bag, mixing with the IKI and H2O in the beaker.This is possible because as stated osmosis is a branched off form of diffusion, in which it is the diffusion of water through a selectively permeable membrane and glucose is one of the substance that is able to go through.Distilled water was then filled into six 250 m L beakers.Each bag was then emerged into one of the six filled beaker and the beakers were labeled by which bag of solution was emerged in it. When the time was up, each bag was removed, blotted and the mass of each bag was recorded.Distilled water was poured into a 250 m L beaker (two-thirds of a cup) with about 4m L of Lugol’s solution (IKI).The color of the sucrose in the beaker was recorded and was tested for glucose.100 m L of the given solution was poured into six different labeled 250 m L beaker.The potato was then sliced into discs that were just about 3 cm thick.The next day, the cores were then removed from the beakers and were blotted gently on a paper towel. The mass difference was calculated and then using the equation: Percent change in mass = Final Mass – Initial Mass/Initial Mass x 100.Determine the solute, pressure and water potential of the sucrose solution given and answer the questions about the possibility if zucchini cores were used with the sucrose solutions.