*No electronic component is perfect and the op amp is no exception.*

Similarly if two admittances are placed in parallel, the total admittance is sum of the admittances.

Therefore the admittance from the output of the op amp to the non inverting input is Likewise the admittance from the non inverting terminal to ground is Using the methodology from before, it can be shown that (eventually) Putting s = jw and R = 1/G gives Therefore, using the principles of nodal analysis, the transfer function for the Wien bridge oscillator has been derived.

From this equation two conclusions can be drawn, both of which are well known conditions for oscillation of the Wien bridge oscillator.

First, for oscillation to occur, there must be zero phase shift from the input to the output.

The above examples use admittances instead of impedances, but the principles are the same and it is left to the engineer to decide which is more suitable.

Once the equations have been derived, the math (depending on the complexity of the circuit) is moderately straightforward to obtain the transfer function.

This approach, although quick, does not always mean the designer has a fundamental understanding of the theory of the circuit operation.

This application note explains how the transfer function of most op amp circuits can be derived by a simple process of nodal analysis.

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Visit Stack Exchange Electrical Engineering Stack Exchange is a question and answer site for electronics and electrical engineering professionals, students, and enthusiasts. Sign up to join this community I am attempting to solve the above circuit for V0. Thus far I've used KCL to say that $$i_3 = i_2 i_1$$ and by ideal op amp function, $$ V_1 = 1V $$ $$V_3 = 2V $$ From there I say that $$ \frac i_2 = \frac $$ But that doesn't really get me any closer to finding V0, what am I missing?

## Comments How To Solve Op Amp Problems

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